Question

Eleven bags of wheat flour, each marked $5$ kg, actually contained the following weights of flour (in kg):
$4.97,5.05,5.08,5.03,5.00,5.06,5.08,4.98,5.04,5.07,5.00$
Find the probability that any of these bags chosen at random contains more than $5$ kg of flour.

• A. $\frac{7}{11}$
• B. $\frac{8}{11}$
• C. $\frac{9}{11}$
• D. None of the above

Answer 1

The correct option is A $\frac{7}{11}$

Given bag of wheat flour are

$4.97,5.05,5.05,5.03,5.00,5.06,5.08,4.98,5.04,5.07,5.00$

The total number of wheat flour bags $=11$.

The number of wheat flour bags contain more than $5$ Kg are $7$.

Then probability of bags chosen at random $=$ $\frac{\text{number of bags more than 5 kg}}{\text{total number of bags}}=\frac{7}{11}$