Question 11
Eleven bags of wheat flour, each marked 5kg, actually contained the following weights of flour (in kg):
4.97, 5.05, 5.08, 5.03, 5.00, 5.06, 5.08, 4.98, 5.04,5.07, 5.00
Find the probability that any of these bags chosen at random contains more than 5 Kg of flour.

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Solution

Number of total bags = 11
Number of bags containing more than 5 kg of flour =7

$P (b a g s c h o s e n a t r a n d o m c o n t a i n s m o r e t h a n 5 k g o f f l o u r) = \frac{N u m b e r o f b a g s c o n t a i n i n g m o r e t h a n 5 k g o f f l o u r}{N u m b e r o f t o t a l b a g s}$
Hence, required probability, $P = \frac{7}{11}$

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Eleven bags of wheat flour, each marked 5 kg, actually contained the following weights of flour (in kg):

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