Question

Empirical formula = C_{​​​​​​2}​​​​​H_​4​​​O
n=2
(​​​​​​n=molecular mass ÷ emperical formula mass
Emperical formula mass = 44
Molecular mass = 88)
molecular formula = n × empirical formula
= 2 × C₂H₄O
= C₄H₈O_​​​2
but the book answer is given that C₄H₈O
Which is correct ? If the book answer is correct , tell me how ?

Answer 1

Might be a printing miitake in the book.