Empirical formula of a compound is $C H_{2} O$ . Its molecular mass is $60$ . The molecular formula will be :

C H_{2} O

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C_{2} H_{4} O_{2}

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C_{3} H_{6} O_{3}

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none of these

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Solution

The correct option is C $C_{2} H_{4} O_{2}$
Assume $α$ is common divisor.
$(12 \times 1 + 2 \times 1 + 16 \times 1) α = 60 α = 60 / 30 = 2$
Hence, molecular formula $= 2 \times C H_{2} O = C_{2} H_{4} O_{2}$

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Similar questions

C H_{2} O

The empirical formula and molecular mass of a compound are $C H_{2} O$ and 180 g respectively. What will be the molecular formula of the compound ?

(a) $C_{9} H_{18} O_{9}$ (b) $C H_{2} O$ (c) $C_{6} H_{12} O_{6}$ (d) $C_{2} H_{4} O_{2}$

C H_{2} O

C H_{2} O

180

C H_{2} O

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