Question

Encircle whichever of the following:

a) is the stronger nucleophile (aprotic solvent) : $F^{-}$or $I^{-}$

b) is the stronger nucleophile (protic solvent) : $F^{-}or$ $I^{-}$

c) is the stronger base : $F^{-}or$ $I^{-}$

d) is the stronger nucleophile (protic solvent) : $N{H}_3$ or $N{H}_{2}N{H}_2$

e) is the better leaving group : $C{H}_{3}CO{O}^{-}or$ $C{H}_{2}S{O}_3^{-}$

Answer 1

A.In aprotic solvents $I^{-}$ is a better nucleophilic due to its bulky size.

B. In polar solvants $F^{-}$ is solvated hence $F^{-}$ is a strong nucleophilic.

C. Since, $HI$ is strongest acid, conjugate bases are weak. So, basic order $F^{-}>I^{-}$

D. Nucleophility of $N{H}_{2}N{H}_2$ is considered stronger because it has two donating groups.

E. A strong acid has a strong leaving group, hence $C{H}_{2}S{O}_3^{-}$ is the better.