Energy of an electron for hydrogen in nth orbit En - - 313-6n2 kcal-mol- Find the value of -n- if the energy of electrons in a certain orbit is - 19-6kcal-mol-

We know, energy of the electron in n^th orbit is E_n = R_H× nbsp; Z^2n^2 where R_H is the rydberg energy constant. Value of E_n is given as 45.64 kcal/mol. ...

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Standard XIII

Chemistry

Bohr's Model of a Hydrogen Atom

Energy of an ...

Question

Energy of an electron for hydrogen in $n^{t h}$ orbit $E_{n} = - \frac{313.6}{n^{2}}$ kcal/mol. Find the value of 'n', if the energy of electrons in a certain orbit is - 19.6kcal/mol.

n = 4

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n = 3

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n = 2

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n = 5

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Solution

The correct option is A n = 4
We know, energy of the electron in $n^{t h}$ orbit is $E_{n} = - R_{H} \times \frac{Z^{2}}{n^{2}}$ where $R_{H}$ is the rydberg energy constant.
Value of $E_{n}$ is given as -45.64 kcal/mol. Equating,
$- 19.6 = - \frac{313.6}{n^{2}}$ [ Z = 1 for hydrogen]
On solving, we get $n^{2}$ = 16
So, n = 4

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Similar questions

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Energy of an electron for hydrogen in nth orbit En=−313.6n2 kcal/mol. Find the value of 'n', if the energy of electrons in a certain orbit is - 19.6kcal/mol.

The correct option is A n = 4We know, energy of the electron in nth orbit is En=−RH×Z2n2 where RH is the rydberg energy constant. Value of En is given as -45.64 kcal/mol. Equating, −19.6=−313.6n2 [ Z = 1 for hydrogen] On solving, we get n2 = 16 So, n = 4

Energy of an electron for hydrogen in $n^{t h}$ orbit $E_{n} = - \frac{313.6}{n^{2}}$ kcal/mol. Find the value of 'n', if the energy of electrons in a certain orbit is - 19.6kcal/mol.