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Question

Energy of photon whose frequency is 1012MHz, will be


A

4.14×103KeV

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B

4.14×102eV

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C

4.14×103MeV

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D

4.14×103eV

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Solution

The correct option is D

4.14×103eV


E(eV)=hve=6.0×1034×1012×1061.6×1019=4.14×103eV.


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