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Standard XII

Chemistry

Conductance of Electrolytic Solution

Equivalent co...

Question

Equivalent conductance of 1M $C H_{3} C O O H$ is 10 $o h m^{- 1} c m^{2} e q u i v^{- 1}$ and that at infinite dilution
is 200 $o h m^{- 1} c m^{2} e q u i v^{- 1}$ . Hence % ionisation of $C H_{3} C O O H$ is __________.

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Solution

The correct option is A 5%
The percentage of ionization is $α = \frac{Λ}{Λ_{0}} \times 100 = \frac{10 o h m^{- 1} c m^{2} e q^{- 1}}{200 o h m^{- 1} c m^{2} e q^{- 1}} \times 100 = 5$ %.

Thus, the percentage of ionization is 5%.

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Similar questions

Equivalent conductance of 1M $C H_{3} C O O H$ is $10 o h m^{- 1} c m^{2} e q u i v^{- 1}$ and that at infinite dilution is $200 o h m^{- 1} c m^{2} e q u i v^{- 1}$ . Hence the percentage ionization of $C H_{3} C O O H$ is:

Q. Equivalent conductance of

1

C H_{3} C O O H

10

o h m^{- 1}

c m^{2}

e q u i^{- 1}

and that at infinite dilution is

200

o h m^{- 1}

c m^{2}

e q u i v^{- 1}

. Hence the

%

ionization of

C H_{3} C O O H

is:

Q. The equivalent conductance of

0.02 M

acetic acid is

1.162 \times 10^{- 3}

ohm

^{- 1}

m o l^{- 1}

m^{2}

. Degree of ionisation '

α

' of

C H_{3} C O O H

is :

(λ_{H^{+}} = 349.83 o h m^{- 1} a n d λ_{C H_{3} C O O^{-}} = 40.89 o h m^{- 1})

Equivalent conductance of 1 M propanoic acid is 10 $o h m^{- 1} c m^{2} e q^{- 1}$ and that at infinite dilution 200 $o h m^{- 1} c m^{2} e q^{- 1}$ . The pH of the propanoic acid solution is:

Q. The resistance of

1 N

solution of acetic acid is

250 o h m

, when measured in a cell having a cell constant of

1.15 {c m}^{- 1}

. The equivalent conductance (in

{o h m}^{- 1} {c m}^{2} {e q u i v}^{- 1}

) of

1 N

acetic acid is:

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Equivalent conductance of 1M CH3COOH is 10 ohm−1cm2equiv−1 and that at infinite dilutionis 200 ohm−1cm2equiv−1. Hence % ionisation of CH3COOH is __________.

The correct option is A 5%The percentage of ionization is α=ΛΛ0×100=10ohm−1cm2eq−1200ohm−1cm2eq−1×100=5 %. Thus, the percentage of ionization is 5%.

Equivalent conductance of 1M $C H_{3} C O O H$ is 10 $o h m^{- 1} c m^{2} e q u i v^{- 1}$ and that at infinite dilution
is 200 $o h m^{- 1} c m^{2} e q u i v^{- 1}$ . Hence % ionisation of $C H_{3} C O O H$ is __________.

The correct option is A 5%
The percentage of ionization is $α = \frac{Λ}{Λ_{0}} \times 100 = \frac{10 o h m^{- 1} c m^{2} e q^{- 1}}{200 o h m^{- 1} c m^{2} e q^{- 1}} \times 100 = 5$ %.

Thus, the percentage of ionization is 5%.