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Preparation of Haloalkane from Alkene

Ethylene reac...

Question

Ethylene reacts with HBr forming X which on reaction with moist $A g_{2} O$ gives Y. When Y is heated with alumina at $300^{0} C$ , compound Z is formed. Then, X and Z are :

bromoethane, ethanol

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ethanol, ethoxyethane

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ethyl bromide, diethyl ether

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bromoethane, ethene

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Solution

The correct option is D bromoethane, ethene
$C H_{2} = C H_{2} + H B r \to C H_{3} - C H_{2} - B r$

$C H_{3} - C H_{2} - B r + A g_{2} O H_{2} O - - \to C H_{3} - C H_{2} - O H + A g B r$

$C H_{3} - C H_{2} - O H + A l_{2} O_{3} 300^{0} C - -- \to C H_{2} = C H_{2}$

Moist $A g_{2} O$ releases $O H^{-}$ in low concentration as $A g O H$ is a weak base.

When ethyl bromide is treated with moist $A g_{2} O$ it gives ethyl alcohol as the major product.

Option D is correct.

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Ethylene reacts with HBr forming X which on reaction with moist Ag2O gives Y. When Y is heated with alumina at 3000C, compound Z is formed. Then, X and Z are :

Ethylene reacts with HBr forming X which on reaction with moist $A g_{2} O$ gives Y. When Y is heated with alumina at $300^{0} C$ , compound Z is formed. Then, X and Z are :