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Question

Evaluate ∣ ∣cosαcosβcosαsinβsinαsinβcosβ0sinαcosβsinαsinβcosα∣ ∣

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Solution

∣ ∣cosαcosβcosαsinβsinαsinβcosβ0sinαcosβsinαsinβcosα∣ ∣

=cosαcosβ(cosαcosβ)+cosαsinβ(cosαsinβ)+sinα(sinαsin2β+sinαcos2β)

=cos2αcos2β+cos2αsin2β+sin2α(1)

=cos2(α)[cos2β+sin2β]+sin2α

=cos2α+sin2α
=1

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