Question

Evaluate : $\frac{\tan {26}^{\circ }}{\cot {64}^{\circ }}$

Answer 1

$\frac{\tan {26}^{\circ }}{\cot {64}^{\circ }}=\frac{\tan ({90}^o-{64}^o)}{\cot {64}^{\circ }}=\frac{\cot {64}^{\circ }}{\cot {64}^{\circ }}=1$