The correct option is A 12
Method I
limx→2x6−24x−16x3+2x−12 (00form)
=limx→2(x−2)(x5+2x4+4x3+8x2+16x+8)(x−2(x2+2x+6)
=limx→2(x5+2x4+4x3+8x2+16x+8)(x2+2x+6)
=25+2(2)4+4(2)3+8(2)2+16(2)+8)(2)2+2(2)+6)
=16814=12
Method II (Applying L'Hospital's rule)
If x=2, x6−24x−16x3+2x−12
limx→2x6−24x−16x3+2x−12 (00form)
=limx→26x5−243x2+2 (Applying L'Hospital's rule)
=6(2)5−243(2)2+2
=16814=12