Excess Fluorine reacts with Ammonia to form :

_{4}

F + HF

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_{3}

+ HF

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_{5}

+ HF

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_{5}

+ NH

_{4}

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Solution

The correct option is B NF $_{3}$ + HF
$N H_{3} + F_{2} \to N F_{3} + H F$
(excess)
$N H_{3} r e d u c e s F_{2} t o F^{-}$

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Similar questions

Q. An excess of

C l_{2}

reacts with ammonia, the products formed are:

Q. Calculate the mass of

N_{2} F_{4}

produced by the reaction of 2 g of ammonia and 8 g of fluorine.

2 N H_{3} + 5 F_{2} \to N_{2} F_{4} + 6 H F

(Molar mass of fluorine = 19 g/mol)

In the laboratory preparation of ammonia, a student used $H_{2} S O_{4}$ for drying instead of CaO. Tell the repercussions of his action.

Ammonia is oxidized according to the following equation:
$4 N H_{3} + 5 O_{2} \to 4 N O + 6 H_{2} O$
How many litres of nitric oxide are formed when 90 litres of oxygen reacts with ammonia? If 4 volume of ammonia reacts with 5 volume of oxygen to give 4 volume of nitric oxide.

Q. Which of the following reactions is/are correct when

C l_{2}

reacts with

N H_{3}

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Excess Fluorine reacts with Ammonia to form :

The correct option is B NF3 + HFNH3+F2→NF3+HF(excess)NH3 reduces F2 to F−

The correct option is B NF $_{3}$ + HF
$N H_{3} + F_{2} \to N F_{3} + H F$
(excess)
$N H_{3} r e d u c e s F_{2} t o F^{-}$