Question

Explain hybridization of central atom in :$Br{F}_5$

Answer 1

The hybridization of $Br{F}_5$ can be determined by the number of lone pairs around iodine and the number of sigma bonds formed between Br and F. Since the central atom iodine has 7 valence electrons out of which 5 electrons form 5 sigma bonds with F atoms and and 2 electrons form 1 lone pair making the stearic number 6 which implies the hybridization of the central atom is $s{p}^3{d}^2$ (involving one 4s, three 4p and two 4d orbitals) where the geometry is octahedral and the shape is square pyramidal.