Question

Explain hybridization of central atom in :$N{H}_4^{+}$

Answer 1

First identify central atom

Hybridisation $=\frac{1}{2}$ [Valence electrons $+$ No. of monovalent atoms $-$ cationic charge $+$ anionic charge]

For, ${NH}_4^{+}$

$=\frac{1}{2}[5+4-1+0]=\frac{8}{2}=4=S^1{P}^3$

Ans :- ${sp}^3$ hybridisation.