f:(−∞,∞)→(−∞,∞) is defined by f(x)=ax+b;a,b∈R(a≠0) then f is
A
injective but not surjective
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B
surjective but not injective
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C
bijective
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D
neither injective nor surjective
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Solution
The correct option is D bijective f(x)=ax+b f′(x)=a So f(x) is increasing if a>0 or f(x) is decreasing if a<0. And f(x) lies in the interal (−∞,∞) in its domain. So f(x) is monotonic & onto, that is, it is bijective