Factorise: $2 x^{2} - 7 x - 15$

(x-5)(2x+3)

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(x-5)(2x+1)

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(x-5)(4x+3)

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(x-6)(2x+3)

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Solution

The correct option is A (x-5)(2x+3)
$2 x^{2} - 7 x - 15$
$= 2 x^{2} - 10 x + 3 x - 15$
$= 2 x (x - 5) + 3 (x - 5)$
$= (x - 5) (2 x + 3)$

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What is the factorization of $2 x^{2} - 7 x - 15$ ?

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