Factorise 2x2−7x+6
(x-2)(2x-1)
(x-2)(2x-3)
(x-1)(2x-3)
(2x-2)(2x-3)
2x2−7x+6=2x2−4x−3x+6
=2x(x−2)−3(x−2)
=(x−2)(2x−3)
Hence the factored form of 2x2−7x+6 is (x−2)(2x−3)
Find the factors of 6x2−13x+6=0
Find the L.C.M. of 6x2−x−1, 3x2+7x+2 and 2x2+3x−2
Factorise: 6(2x−3x)2−2(2x−3x)−20