wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Factorise 32a4−8a4

A
8a2(2a1)(2a+1)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
8a(2a1)(2a+1)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
4a2(2a1)(2a+1)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
32a2(2a+1)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 8a2(2a1)(2a+1)
32a48a4
Taking 8 a2 common we have
=8a2(4a21
= 8a2((2a)21) {a2b2=(a+b)(ab)}
= 8a2(2a1)(2a+1)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Method of Identities
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon