Factorise
$7 a^{3} + 56 b^{3}$

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Solution

7a³ + 56 b³
= 7 (a³ + 8b³)
= 7 [a³ + (2b)³]
= 7 (a + 2b)(a² - 2ab + 4b²)

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(7 a^{3} + 56 b^{3})

a^{6} - 7 a^{3} - 8.

Factorise the expression 15 a^{3} b + 35 a b^{3} .

Factorise:

$a^{6} - 7 a^{3} - 8$

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