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Algebraic Identities

Factorise 7a3...

Question

Factorise
$7 a^{3} + 56 b^{3}$

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Solution

7a³ + 56 b³
= 7 (a³ + 8b³)
= 7 [a³ + (2b)³]
= 7 (a + 2b)(a² - 2ab + 4b²)

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(7 a^{3} + 56 b^{3})

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