Factorise:
$8 - 4 a - 2 a^{3} + a^{4}$

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Solution

$8 - 4 a - 2 a^{3} + a^{4}$

= 4(2 – a) – a³ (2 – a)

= (2 – a) (4 – a³)

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Similar questions

Factorise:
$8 - 4 a - 2 a^{3} + a^{4}$

a^{4} - 2 a^{3} - 4 a + 8

a^{4} - 2 a^{3} - 4 a + 8

Factorise by grouping method:

$a^{4} - 2 a^{3} - 4 a + 8$

a^{4} - 2 a^{3} - 4 a + 8

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