The correct option is A (a^2 + 1) (a + 1) (a 1) nbsp; a^4 1 =(a^2)^2 1^2 =(a^2+1)(a^2 1) =(a^2+1)(a+1)(a 1) ...

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Factorisation by Common Factors

Factorize: a...

Question

Factorize:
$a^{4} - 1$ .

(a^{2} + 1) (a + 1) (a - 1)

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(a^{3} + 1) (a + 1) (a - 1)

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(a^{2} + 1) (2 a + 1) (a - 1)

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(a^{3} + 1) (a + 1) (a + 1)

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Solution

The correct option is A $(a^{2} + 1) (a + 1) (a - 1)$
$a^{4} - 1$
$= (a^{2})^{2} - 1^{2}$
$= (a^{2} + 1) (a^{2} - 1)$
$= (a^{2} + 1) (a + 1) (a - 1)$

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