Factorize $a^{4} - 2 a^{3} - 4 a + 8$ by the grouping method

(a - 2) (a^{3} - 5)

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(a - 4) (a^{3} - 4)

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(a - 2) (a^{3} - 4)

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(a - 2) (a^{3} - 7)

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Solution

The correct option is D $(a - 2) (a^{3} - 4)$
Given expression is $a^{4} - 2 a^{3} - 4 a + 8$
Taking $a^{3}$ common from the first two terms and $4$ from the last two, we get:

$a^{3} (a - 2) - 4 (a - 2)$
$= (a - 2) (a^{3} - 4)$

Hence, $a^{4} - 2 a^{3} - 4 a + 8 = (a - 2) (a^{3} - 4)$ .

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a^{4} - 2 a^{3} - 4 a + 8

a^{4} - 2 a^{3} - 4 a + 8

a^{4} - 2 a^{3} - 4 a + 8

Factorise by grouping method:

$a^{4} - 2 a^{3} - 4 a + 8$

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