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Question

Factorize each of the following algebraic expression:
x2 − y2 − 4xz + 4z2

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Solution

x2-y2-4xz+4z2=(x2-4xz+4z2)-y2=[x2-2×x×2z+(2z)2]-y2=(x-2z)2-y2=[(x-2z)-y][(x-2z)+y]=(x-2z-y)(x-2z+y)=(x+y-2z)(x-y-2z)

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