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Question

Factorize the following:
5(3a22a)(63a2+2a)

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Solution

The given expression 5(3a22a)(63a2+2a) can be factorized as follows:

5(3a22a)(63a2+2a)=5(3a22a)[6(3a22a)]=5y(6y)(Assuming3a22a=y)=56y+y2=y26y+5=y25yy+5=y(y5)1(y5)=(y5)(y1)=(3a22a5)(3a22a1)(3a22a=y)=(3a2+3a5a5)(3a23a+a1)=[3a(a+1)5(a+1)][3a(a1)+1(a1)]=(3a5)(a1)(a+1)(3a+1)

Hence, the factorization of 5(3a22a)(63a2+2a) is (3a5)(a1)(a+1)(3a+1).

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