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Question

Factorize the following equation by the grouping method
24a3+37a2−5a

A
a(a3)(8a1)
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B
a(a+3)(a1)
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C
a(3a+1)(a1)
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D
a(3a+5)(8a1)
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Solution

The correct option is B a(3a+5)(8a1)
24a3+37a25a
=a(24a2+37a5)
=a(24a2+40a3a5)
=a[8a(3a+5)1(3a+5)]
=a(3a+5)(8a1)

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