Factors of $4 X^{2} - Y^{2} + 2 X - 2 Y - 3 X Y$ are

(x + y) (4 x + y - 2)

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(x - y) (4 x + y + 2)

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(x + y) (4 x - y - 2)

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(x y + 2)

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Solution

The correct option is C $(x - y) (4 x + y + 2)$
On putting $X = Y$ we observed that expression turns out to zero which means $(x - y)$ is one factor
$4 x^{2} - y^{2} + 2 x - 2 y - 3 x y$ it can be written as follow
$4 x (x - y) + y (x - y) + 2 (x - y)$
$(x - y) (4 x + y + 2)$

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