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Question

# Figure below shows a fixed wedge on which two blocks of masses 2 kg and 3 kg are placed on its smooth inclined surfaces. When the two blocks are released from rest, find the acceleration of centre of mass of the two blocks.

A
31g10
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B
g
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C
g/2
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D
g/5
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Solution

## The correct option is A √31g10Block A slides with acceleration g2 and block B slides with acceleration √3g2. Now the acceleration of centre of mass of the system of blocks A and B can be given both in x and in y directions as ax=3×√3g2cos60∘−2×g2sin30∘5=√3g20 and ay=3×√3g2sin60∘+2×g2sin30∘5=11g20 Thus acceleration of the centre of mass of the system is given as aCM=√a2x+a2y=√(√3g20)2+(11g20)2=√3110g

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