Figure shows a fixed wedge on which two blocks of masses 2 kg and 3 kg are placed on its smooth inclined surfaces. When the two blocks are released from rest, find the acceleration of centre of mass of the two blocks.

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Solution

Acceleration if they move together $a = \frac{10}{100 + 1}$
Reqiuent friction for acceleration
$F = m a = \frac{10}{10_{1}} N$
max applicable friction = mmp $= 0.5 \times 10 = 5 N$
$∴ f = \frac{10}{10} N = 0.1 N$

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Figure shows a fixed wedge on which two blocks of masses 2 kg and 3 kg are placed on its smooth inclined surfaces. When the two blocks are released from rest, find the acceleration of centre of mass of the two blocks.

Acceleration if they move together a=10100+1Reqiuent friction for accelerationF=ma=10101Nmax applicable friction = mmp =0.5×10=5N∴f=1010N=0.1N

Acceleration if they move together $a = \frac{10}{100 + 1}$
Reqiuent friction for acceleration
$F = m a = \frac{10}{10_{1}} N$
max applicable friction = mmp $= 0.5 \times 10 = 5 N$
$∴ f = \frac{10}{10} N = 0.1 N$