Question

Figure (i) shows two capacitors connected in series and connected by a battery. The graph (ii) shows the variation of potential as one moves from left to right on the branch AB containing the capacitors. Then :

• A. $C_1=C_2$
• B. $C_1<C_2$
• C. $C_1>C_2$
• D. $C_1$ and $C_2$ cannot be compared

Answer 1

Answer: (C)

$C_1>C_2$

According to graph we can say that the potential across $C_2$ is greater than of $C_1$.
As they are in series so charge on both is equal.
Since , $V=q/C\Rightarrow C_1>C_2$