Figure show some of the electric field lines corresponding to an electric field. The figure suggest that (E= electric field, V=potential).
A
EA>EB
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B
EA<EB
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C
VA>VB
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D
VA<VB
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Solution
The correct options are BEA>EB DVA<VB Denser field lines give more electric field. At point B field lines are far away from each other compare to the point A. So EA>EB and using E=−dVdr we can say that VA<VB so, (A),(D) are correct option.