Time taken by the bob to move from A to C is t1 and from C to O is t2. The time period of this simple pendulum is
A
(t1+t2)
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B
2(t1+t2)
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C
3(t1+t2)
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D
4(t1+t2)
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Solution
The correct option is D4(t1+t2) The total time taken by the bob to move from A to O is (t1+t2),
which is 14th time of one full cycle of the pendulum.
Therefore, time period of pendulum i.e. time taken by pendulum to complete one oscillation from A to B and back to A will be 4(t1+t2).