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Question

Figure shows an oscillating pendulum.

Time taken by the bob to move from A to C is t1 and from C to O is t2. The time period of this simple pendulum is

A
(t1 + t2)
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B
2 (t1 + t2)
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C
3 (t1 + t2)
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D
4 (t1 + t2)
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Solution

The correct option is D 4 (t1 + t2)
The total time taken by the bob to move from A to O is (t1+t2),
which is 14th time of one full cycle of the pendulum.
Therefore, time period of pendulum i.e. time taken by pendulum to complete one oscillation from A to B and back to A will be 4 (t1 + t2).

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