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Question

Figure shows some of the electric field lines corresponding to an electric field. The figure suggests that


(a) EA > EB > EC
(b) EA = EB = EC
(c) EA = EC > EB
(d) EA = EC < EB

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Solution

(c) EA = EC > EB

The crowding of electric field lines at a point shows the strength of the field at that point. More the crowding of field lines, more will be the field strength. At points A and C, there's equal crowding, whereas at point B, the lines are far apart. Therefore, EA = EC > EB

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