Figure shows three points A, B and C in a region of uniform electric field E. The line AB is perpendicular and BC is parallel to the field lines. Then which of the following holds good?
Where $V_{A}, V_{B}$ and $V_{C}$ represent the electric potential at the points A, B and C respectively.

V_{A} = V_{B} = V_{C}

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V_{A} = V_{B} > V_{C}

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V_{A} = V_{B} < V_{C}

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V_{A} > V_{B} = V_{C}

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Solution

The correct option is B $V_{A} = V_{B} > V_{C}$
Electric line of forces constitute electric field. In an electric field electric line of force always flow form higher potential to lower potential. Hence, A and B are at same higher potential and B is at lower potential. Thus $V_{A} = V_{B} > V_{C}$

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Figure shows three points A, B and C in a region of uniform electric field E. The line AB is perpendicular and BC is parallel to the field lines. Then which of the following holds good?Where VA,VB and VC represent the electric potential at the points A, B and C respectively.

The correct option is B VA=VB>VCElectric line of forces constitute electric field. In an electric field electric line of force always flow form higher potential to lower potential. Hence, A and B are at same higher potential and B is at lower potential. Thus VA=VB>VC

Figure shows three points A, B and C in a region of uniform electric field E. The line AB is perpendicular and BC is parallel to the field lines. Then which of the following holds good?
Where $V_{A}, V_{B}$ and $V_{C}$ represent the electric potential at the points A, B and C respectively.

The correct option is B $V_{A} = V_{B} > V_{C}$
Electric line of forces constitute electric field. In an electric field electric line of force always flow form higher potential to lower potential. Hence, A and B are at same higher potential and B is at lower potential. Thus $V_{A} = V_{B} > V_{C}$