Fill in the blanks in the following expansions:

(1) 2(3 + 5) = 2 × ........ + 2 × ......
(2) 6 (...... + ......) = 6 ×7 + 6 × 4
(3) 10 (...... − ......) = 10 × 9 − 10 × 7

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Solution

(1) 2(3 + 5) = 2 × 3 + 2 × 5

(2) 6 ( 7 + 4 ) = 6 ×7 + 6 × 4

(3) 10 ( 9 − 7 ) = 10 × 9 − 10 × 7

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