Question

Find $\frac{3}{7}+\left(\frac{-6}{11}\right)+\left(\frac{-8}{21}\right)+\frac{5}{22}$

Answer 1

$\frac{3}{7}+(-\frac{6}{11})+(-\frac{8}{21})+\frac{5}{22}$

$=\frac{3}{7}-\frac{6}{11}-\frac{8}{21}+\frac{5}{22}$

$=(\frac{3}{7}-\frac{8}{21})+(\frac{5}{22}-\frac{6}{11})$

$=\frac{9-8}{21}+\frac{5-12}{22}$

$=\frac{1}{21}+\frac{-7}{22}$

$=\frac{1}{21}-\frac{7}{22}$

$=\frac{22-147}{21\times 22}$

$=-\frac{125}{462}$