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Question

Find ddx of y=tan x.

A
cos2 x
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B
tan2 x
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C
sec2 x
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D
cosec2 x
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Solution

The correct option is C sec2 x
d(tanx)dx=d(sinxcosx)dx
=cos xd(sin x)dxsin xd(cos x)dxcos2x
=cos x cos xsin x(sin x)cos2x
=cos2x+sin2xcos2x=1cos2x=sec2x

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