Find.
(i) $(- 7) - 8 - (- 25)$
(ii) $(- 13) + 32 - 8 - 1$
(iii) $(- 7) + (- 8) + (- 90)$
(iv) $50 - (- 40) - (- 2)$

i) 10 i i) 10 i i i) 105 i v) 92

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i) 10 i i) 10 i i i) 105 i v) 8

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i) 10 i i) 40 i i i) - 105 i v) 92

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i) 10 i i) 10 i i i) - 105 i v) 92

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Solution

The correct option is B $i) 10 i i) 10 i i i) - 105 i v) 92$
$(i) (- 7) - 8 - (- 25)$

$= - 15 + 25 = 10$

$(i i) - 13 + 32 - 8 - 1$

$- 13 - 8 - 1 + 32$

$= - 22 + 32 = 10$

$(i i i) - 7 + (- 8) + (- 90)$

$= - 7 - 8 - 90$

$= - 105$

$(i v) 50 - (- 40 - (- 2))$

$= 50 + 40 + 2$

$= 92$

Suggest Corrections

Similar questions

Find:

(a) (− 7) − 8 − (− 25)

(b) (− 13) + 32 − 8 − 1

(d) 50 − (− 40) − (− 2)

(10 + \sqrt{3}) (2 + \sqrt{5})

(\sqrt{5} + \sqrt{3})^{2}

(\sqrt{13} - \sqrt{2}) (\sqrt{13} + \sqrt{12})

(8 + \sqrt{3}) (8 - \sqrt{3})

8^{3} = 512

32^{3 / 5} = 8

7^{- 2} = \frac{1}{49}

10^{- 2} = 0.01

Find the cubes of:

(i) $\frac{3}{7}$ (ii) $\frac{8}{9}$ (iii) $\frac{10}{13}$

(iv) $1 \frac{2}{7}$ (v) $2 \frac{1}{2}$

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