Find out the force of attraction between two bodies having masses 50 kg and 75 kg which is placed at a distance equal to 66.7m ?

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Solution

Dear student,

Let mass of two body be m₁ and m₂be 50 kg and 70 kg.
Distance between two bodies be 66.7 m
The force of attraction between the body is

$F = G \frac{m_{1} m_{2}}{r^{2}} F = \frac{6.67 \times 10^{- 11} \times 50 \times 75}{66.7 \times 66.7} F = \frac{25012.5 \times 10^{- 11}}{4448.89} F = 5.62 \times 10^{- 11} N$

Regards.

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Find out the force of attraction between two bodies having masses 50 kg and 75 kg which is placed at a distance equal to 66.7m ?

Dear student, Let mass of two body be m1 and m2 be 50 kg and 70 kg. Distance between two bodies be 66.7 m The force of attraction between the body is F=Gm1 m2r2F=6.67×10-11×50×7566.7×66.7F=25012.5×10-114448.89F=5.62 ×10-11 N Regards.