Question

Find the additive inverse of $\frac{9}{2+i\sqrt{5}}$

Answer 1

Given,

$\frac{9}{2+i\sqrt{5}}+x=0$

$=>x=-\frac{9}{2+i\sqrt{5}}\times \frac{2-i\sqrt{5}}{2-i\sqrt{5}}$

$=>x=-(2-i\sqrt{5})$

Therefore,additive inverse is $-(2-i\sqrt{5}).$