Find the angle between the pair of lines →r=3i+2j−4k+λ(i+2j+2k) and →r=5i−2k+μ(3i+2j+6k).
Given lines are →r=3i+2j−4k+λ(i+2j+2k)
and →r=5i−2k+μ(3i+2j+6k)
We know, angle between →r=→a1+λ→b1 and →r=→a2+λ→b2 is given by,
cosθ=→b1.→b2∣∣∣→b1∣∣∣∣∣∣→b2∣∣∣
⇒cosθ=(i+2j+2k).(3i+2j+6k)√12+22+22√32+22+62
=3+4+12√9√49=1921
⇒θ=cos−1(1921)