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Question

Find the angle between the pair of lines r=3i+2j4k+λ(i+2j+2k) and r=5i2k+μ(3i+2j+6k).

A
cos1(1921)
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B
sin1(1921)
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C
cos1(2021)
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D
sin1(2021)
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Solution

The correct option is B cos1(1921)

Given lines are r=3i+2j4k+λ(i+2j+2k)

and r=5i2k+μ(3i+2j+6k)

We know, angle between r=a1+λb1 and r=a2+λb2 is given by,

cosθ=b1.b2b1b2

cosθ=(i+2j+2k).(3i+2j+6k)12+22+2232+22+62

=3+4+12949=1921

θ=cos1(1921)


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