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Question

Find the area of a triangle whose sides. are 18 cm , 10 cm and 14 cm.

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Solution

Given sides are 18cm,10cm and 14cm

Area of triangle =s(sa)(sb)(sc)

a=18cm,b=10cm and c=14cm

s=a+b+c2=18+10+142=422=21cm

Area =21(2118)(2110)(2114)
=21×3×11×7
=2111sqcm

Hence, the answer is 2111sqcm.

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