Find the area of the sector of a circle having radius 6 cm and of angle 30°. [Take π = 3.14]

Open in App

Solution

We have $r = 6 cm and θ = 30 °$
Now, Area of sector = $\frac{θ}{360^{°}} \times π r^{2} = \frac{30 °}{360 °} \times 3.14 \times 36 = 9.42 {cm}^{2}$
Hence, the area of the sector of the circle is 9.42 cm².

Suggest Corrections

Similar questions

4 c m

30^{\circ},

π = 3.14) .

18 cm

120^{\circ}

π = 3.14

The area of a sector (in $c m^{2}$ )of a circle with radius 6 cm if angle of the sector is $70^{\circ}$ will be __ . ( Take $π$ = $\frac{22}{7}$ )

Find the area of a sector of a circle with radius 6 cm if angle of the sector is 60°.

The area of a sector (in $c m^{2}$ )of a circle with radius 6 cm if angle of the sector is $70^{\circ}$ will be __ . $T a k e π = \frac{22}{7}$

Join BYJU'S Learning Program