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Question

Find the Cartesian equation of the following plane:
r.(2^i+3^j4^k)=1

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Solution

Given vector equation is r.(2^i+3^j4^k)=1 ...(ii)

for any arbitrary point P(x,y,z) on the plane , position vector r is given by x^i+y^j+z^k

Substituting the value of r in Eq. (ii), we obtain

(x^i+y^j+z^k).(2^i+3^j4^k)=12x+3y4z=1

which is the required Cartesian form.


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