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Question

Find the coefficient of x17 in the expansion (x+x2+x3+..............x6)6(1+x+x2+x3+.........)


A

7756

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B

9604

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C

3493

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D

11914

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Solution

The correct option is B

9604


Coefficient of x17 in (x+x2+x3+............x6)6(1+x+x2+x3+.........)

Coefficient of x11 in (xx6)6(1x)7

Coefficient of x11 in (x6x6)6(1x)7

Coefficient of x11 in (16x6)(1+7C1x+8C2x2+9C3x3+..............) = 17C11611C6=17C6611C5


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