Find the cost of plastering the inner surface of a well at $R s 9.50$ per $m^{2}$ if it is $21 m$ deep and diamter of its top is $6 m$

Open in App

Solution

ht= deep = $21 m$
diameter $= 6 m$
radius $= \frac{d}{2} = 3 m$
Cost of plastering the inner well $= R s . 9.50 / m^{2}$
Inner surface of the well $= π r h$
$r = 3 m, h = 21 m$
CSA= Inner surface $= 2 \times π \times r \times h$
$= 2 \times \frac{22}{7} \times 3 \times 21$
$\Rightarrow 2 \times 198 = 396 m^{2}$
Total cost of plastering $= R s . 9.50 \times 396$
$= R s . 3762$

Suggest Corrections

Similar questions

Q. Find the cost of plastering the inner surface of a well at Rs 9.50 per m², if it is 21 m deep and diameter of its top is 6 m.

How many cubic metres of earth must be dugout to sink a well 21 m deep and 6 m diameter? Find the cost of plastering the inner surface of the well at Rs. 9.50 per $m^{2}$ .

Q. The inner diameter of a circular well is

3.5 m

. It is

10 m

deep. Find the cost of plastering this curved surface at the rate of

R s .40

per

m^{2}

Q. The inner diameter of a circular well is

3.5 m

. It is

10 m

deep. Find

(i)

its inner curved surface area

(i i)

the cost of plastering the curved surface at the rate of

R s . 40

per

m^{2}

The inner diameter of a circular well is $3.5 m .$ It is $10 m$ deep. Find :

$(i)$ inner curved surface area.

$(i i)$ the cost of plastering this curved surface at the rate of $R s . 40$ per $m^{2}$ .

Join BYJU'S Learning Program

Find the cost of plastering the inner surface of a well at Rs9.50 per m2 if it is 21 m deep and diamter of its top is 6 m

ht= deep =21 mdiameter =6 mradius =d2=3 mCost of plastering the inner well =Rs.9.50/m2Inner surface of the well =πrhr=3m,h=21 mCSA= Inner surface =2×π×r×h =2×227×3×21 ⇒2×198=396 m2Total cost of plastering =Rs.9.50×396 =Rs.3762

Find the cost of plastering the inner surface of a well at $R s 9.50$ per $m^{2}$ if it is $21 m$ deep and diamter of its top is $6 m$