Find the cost of renovating the walls and the floor of a hall that measures 10m - 45m - 6m if the cost is Rs 48 per square meter-

Area of the floor =L× B = 45m× 10m = 450m^2 Area of the walls = 2(BH + LH)= 2(45× 6 + 10× 6) = 2(270+ 60) =660m^2 Total area to be renovated = 66 ...

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Standard VIII

Mathematics

Total Surface Area of a Cuboid

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Question

Find the cost of renovating the walls and the floor of a hall that measures 10m $\times$ 45m $\times$ 6m if the cost is Rs 48 per square meter.

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Solution

Area of the floor $= L \times B = 45 m \times 10 m = 450 m^{2}$
Area of the walls $= 2 (B H + L H) = 2 (45 \times 6 + 10 \times 6) = 2 (270 + 60) = 660 m^{2}$
Total area to be renovated $= 660 + 450 = 1110 m^{2}$
Cost of renovating the walls and the floor $= 48 \times 1110 m^{2} = R s . 53, 280$

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Find the cost of renovating the walls and the floor of a hall that measures 10m × 45m × 6m if the cost is Rs 48 per square meter.

Area of the floor =L×B=45m×10m=450m2Area of the walls =2(BH+LH)=2(45×6+10×6)=2(270+60)=660m2Total area to be renovated =660+450=1110m2Cost of renovating the walls and the floor =48×1110m2=Rs.53,280

Find the cost of renovating the walls and the floor of a hall that measures 10m $\times$ 45m $\times$ 6m if the cost is Rs 48 per square meter.

Area of the floor $= L \times B = 45 m \times 10 m = 450 m^{2}$
Area of the walls $= 2 (B H + L H) = 2 (45 \times 6 + 10 \times 6) = 2 (270 + 60) = 660 m^{2}$
Total area to be renovated $= 660 + 450 = 1110 m^{2}$
Cost of renovating the walls and the floor $= 48 \times 1110 m^{2} = R s . 53, 280$