Find the cubes of the following.
1=1.6
2=0.04
3=3/11

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Solution

1.6 x 1.6 x 1.6 = 4.096 ; 0.04 x 0.04 x 0.04 = 0.000064 ; (3/11)^3 = 27/1331 ;

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\frac{7}{5 - 2 \frac{2}{3}} \div \frac{3 - \frac{2}{3 - 1 \frac{1}{2}}}{4 - 1 \frac{1}{2}} - \frac{5}{7} \times ⎡ ⎣ \frac{7}{10} + 1 \frac{1}{5} \times \frac{3 \frac{1}{3} - 2 \frac{1}{2}}{2 \frac{5}{21} - 2} ⎤ ⎦

+ \frac{\frac{3}{1.6} + \frac{5}{3.2}}{\frac{5}{4.8} + \frac{1}{9.6}}

3 \frac{1}{5}

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1 = \frac{1}{2} \{1 \times (1 + 1)\} 1 + 2 = \frac{1}{2} \{2 \times (2 + 1)\} 1 + 2 + 3 = \frac{1}{2} \{3 \times (3 + 1)\} 1 + 2 + 3 + 4 = \frac{1}{2} \{4 \times (4 + 1)\}

Find the cubes of:

(1) (1)³

(2) (−2)³

(3) (3)³

(4) (4)³

(5) (−5)³

(6) (2³)³

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