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Question

Find the derivative of $$\displaystyle\, y \, =\,  \frac{1}{x} \, +\,  \frac{1}{x^2} \, +\,  \frac{3}{x^3}$$


Solution

$$y=\dfrac{1}{x}+\dfrac{1}{x^2}+\dfrac{3}{x^3}$$

$$\dfrac{dy}{dx}=-\dfrac{1}{x^2}-\dfrac{2}{x^3}-\dfrac{9}{x^4}$$

Mathematics

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